To design a small program that determines whether a given year is a leap year, we must first clarify the definition and calculation method of a leap year. First, a leap year has 366 days, while a common year has 365 days. Next, we need to determine the calculation method for leap years, which has … Read more
Perpetual Calendar:Source Code: #include <stdio.h> #include <stdlib.h> int year(int y){ // Determine if it's a leap year if ((y % 4 == 0) && (y % 100 != 0) || y % 400 == 0) return 366; // Leap year else return 365; // Common year } void printfStar() // Custom function { printf("*****************************\n"); } … Read more
1. P5711 [Deep Foundation 3. Example 3] Leap Year Determination #include<iostream>using namespace std; int main(){ int n; cin >> n; if(n % 400 == 0 || (n % 100 != 0 && n % 4 == 0)){ cout << 1; } else { cout << 0; } return 0;} 2. B2042 Determine if a Number … Read more
int happy(int year, int month, int day){ if (month > 12 || month < 1) { return -1; } else { if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)//Leap year { if (month == 2) { if (day > 29 || day < 1) return … Read more